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NS pairs

EW pairs





Datum value is the average score. Where a bracketed value is included this is calculated without the outliers.

Holiday Bridge (2015) 17 December

NS pair 1 Section a Mike Macavoy Anthony Y0ung	Bd Rd Con Dc Ld Res EW   Score   MP 1 1 1 S Q +2 1 140 01 - 03 2 1 1 W 7 -1 1 050 04 - 00 3 1 2 N T -2 1 -100 02 - 02 4 1 4 E A +1 1 -650 03 - 01 5 1 3 E 8 = 1 -110 00 - 04 6 1 2 S 2 -2 1 -100 00 - 04 7 1 3 N N 3 = 1 600 00 - 04 8 2 2 E 7 +1 3 -140 02 - 02 9 2 5 W A = 3 -650 00 - 04 10 2 3 N N T = 3 600 03 - 01 11 2 5 W 5 -1 3 050 04 - 00 12 2 2 E J +1 3 -140 02 - 02 13 2 1 N N 9 -1 3 -100 04 - 00 14 2 3 E A -1 3 050 04 - 00 15 3 4 S Q +2 2 680 03 - 01 16 3 3 N E 3 = 2 -600 00 - 04 17 3 3 S 2 -1 2 -50 02 - 02 18 3 4 N A = 2 620 02 - 02 19 3 2 S 2 -1 2 -50 04 - 00 20 3 4 N A +1 2 650 01 - 03 21 3 5 N 9 -2 2 -200 01 - 03
NS pair 2 Section a Liz Macavoy Carol Young	Bd Rd Con Dc Ld Res EW   Score   MP 1 3 1 S 8 +2 3 140 01 - 03 2 3 1 W 4 +2 3 -110 02 - 02 3 3 3 E J +2 3 -200 00 - 04 4 3 4 E 7 +1 3 -650 03 - 01 5 3 3 E Q -1 3 050 04 - 00 6 3 1 N A +1 3 110 04 - 00 7 3 3 N N 4 +2 3 660 03 - 01 8 1 4 E T -1 2 050 04 - 00 9 1 4 N J -2 2 -100 03 - 01 10 1 3 N N 3 = 2 600 03 - 01 11 1 4 W A = 2 -130 02 - 02 12 1 2 W 9 +1 2 -110 04 - 00 13 1 2 E J +1 2 -140 01 - 03 14 1 2 E 7 = 2 -110 02 - 02 15 2 4 S 5 +2 1 680 03 - 01 16 2 2 N E T +1 1 -150 02 - 02 17 2 2 S 2 = 1 110 04 - 00 18 2 5 N 9 = 1 600 00 - 04 19 2 3 S 2 -2 1 -100 02 - 02 20 2 4 N T +1 1 650 01 - 03 21 2 4 S 9 -2 1 -200 01 - 03
NS pair 3 Section a Bill Darling John Mitchell	Bd Rd Con Dc Ld Res EW   Score   MP 1 2 1 N 8 +3 2 170 04 - 00 2 2 2 N E 9 = 2 -120 00 - 04 3 2 2 N T -1 2 -50 04 - 00 4 2 4 E A +2 2 -680 00 - 04 5 2 3 N J -1 2 -100 02 - 02 6 2 1 N E A = 2 -90 02 - 02 7 2 3 N N 4 +2 2 660 03 - 01 8 3 3 N E T +1 1 -430 00 - 04 9 3 3 N 4 -2 1 -100 03 - 01 10 3 3 N S 6 -1 1 -100 00 - 04 11 3 4 x W A = 1 -510 00 - 04 12 3 2 E 3 +3 1 -200 00 - 04 13 3 2 E J +1 1 -140 01 - 03 14 3 4 E A = 1 -420 00 - 04 15 1 4 S 8 +1 3 650 00 - 04 16 1 3 N E 5 -1 3 100 04 - 00 17 1 4 x N A -1 3 -100 00 - 04 18 1 3 N S 2 +2 3 660 04 - 00 19 1 4 x S 3 -2 3 -300 00 - 04 20 1 3 N S 4 +3 3 690 04 - 00 21 1 L P N 3 0 04 - 00