Te Anau Bridge Club        

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NS pairs

EW pairs

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Hand records



Datum value is the average score. Where a bracketed value is included this is calculated without the outliers.

Stuart Pairs (2025) 24 September

EW pair 1 Section b Wendy Holder Marie Galland	Bd Rd Con Dc Ld Res NS   Score   MP 1 1 6 NT N 5 = 1 990 2 2 1 4 E A -1 1 050 2 3 1 3 N 5 +1 1 170 2 4 1 4 E K = 1 -130 3 5 1 5 S A -1 1 -100 4 6 1 3 NT S 4 +2 1 460 0 7 3 2 NT E 2 = 3 -120 0 8 3 3 S 6 -2 3 -100 6 9 3 4 W 9 = 3 -620 2 10 3 1 NT N 5 +1 3 120 4 11 3 3 S K -1 3 -50 4 12 3 2 E A +1 3 -140 6 13 2 3 E 5 = 2 -140 6 14 2 3 N A -1 2 -50 5 15 2 2 E 8 = 2 -110 0 16 2 1 NT W A = 2 -90 1 17 2 4 W 5 +2 2 -480 5 18 2 4 S 5 = 2 620 2 19 4 4 N A -2 4 -100 3 20 4 5 S A = 4 600 0 21 4 2 NT S 3 -1 4 -100 1 22 4 3 W A +1 4 -170 6 23 4 1 E J +2 4 -140 2 24 4 2 E 6 -1 4 050 6
EW pair 2 Section b Trevor Lyall Bruce Campbell	Bd Rd Con Dc Ld Res NS   Score   MP 1 2 3 NT N 3 +1 3 430 6 2 2 5 E A -3 3 150 0 3 2 1 S 6 +1 3 090 6 4 2 2 N 6 = 3 110 0 5 2 5 S 6 -1 3 -100 4 6 2 2 NT S 4 +1 3 150 4 7 1 3 W K = 2 -140 2 8 1 3 N 7 = 2 140 2 9 1 3 NT E 2 = 2 -600 0 10 1 4 N 2 = 2 620 0 11 1 3 W 3 -3 2 150 0 12 1 1 E 9 +1 2 -110 4 13 3 2 W K = 4 -90 0 14 3 5 S 4 -1 4 -50 5 15 3 2 E 8 +1 4 -140 2 16 3 2 N 9 -2 4 -100 4 17 3 4 W K +1 4 -450 2 18 3 4 S 5 +1 4 650 0 19 4 3 N 4 = 1 140 0 20 4 5 W = 1 -600 6 21 4 3 N 2 -1 1 -100 1 22 4 4 W A -3 1 300 0 23 4 2 W K +1 1 -140 2 24 4 4 S K +1 1 450 2
EW pair 3 Section b Caryl Marshall Marg Cockburn	Bd Rd Con Dc Ld Res NS   Score   MP 1 4 3 NT S 2 +3 2 490 4 2 4 6 x N A -3 2 -800 6 3 4 3 N A = 2 140 4 4 4 5 E 8 +1 2 -620 6 5 4 3 NT N 7 +2 2 660 0 6 4 2 N A = 2 110 6 7 2 3 W K +1 4 -170 5 8 2 3 x S 6 = 4 530 0 9 2 4 NT E 7 = 4 -630 4 10 2 5 N A -2 4 -200 6 11 2 3 NT E Q = 4 -400 6 12 2 4 E A -1 4 050 1 13 3 2 E Q = 1 -110 3 14 3 3 S 6 +1 1 130 1 15 3 3 E 8 +1 1 -170 5 16 3 1 NT W A = 1 -90 1 17 3 4 W 5 +2 1 -480 5 18 3 2 S A +4 1 230 4 19 1 4 N A -2 3 -100 3 20 1 4 S A = 3 130 2 21 1 2 W J +1 3 -140 5 22 1 3 W 7 = 3 -140 4 23 1 3 W J +1 3 -170 6 24 1 3 NT S K +2 3 460 0
EW pair 4 Section b Margaret Henderson Joan Cockburn	Bd Rd Con Dc Ld Res NS   Score   MP 1 1 6 NT x S A = 4 1230 0 2 1 4 E A +1 4 -450 4 3 1 4 N 5 = 4 420 0 4 1 3 E A +1 4 -130 3 5 1 5 S A -1 4 -100 4 6 1 2 NT S 5 +4 4 240 2 7 2 3 W Q +1 1 -170 5 8 2 4 S 6 -1 1 -50 4 9 2 3 NT E 3 +2 1 -660 6 10 2 2 N A +2 1 130 2 11 2 3 W 3 -2 1 100 2 12 2 2 E 9 -1 1 050 1 13 4 2 E 5 = 3 -110 3 14 4 3 S 6 +1 3 130 1 15 4 3 E 8 +1 3 -170 5 16 4 2 W T = 3 -110 6 17 4 2 W 8 +3 3 -200 0 18 4 2 S 6 +3 3 200 6 19 3 2 E 6 = 2 -110 6 20 3 3 E Q -1 2 100 4 21 3 3 E 9 = 2 -140 5 22 3 4 N K -1 2 -50 2 23 3 2 W K +1 2 -140 2 24 3 3 N Q +1 2 130 4