Alexandra Bridge Club : Detailed data for Alexandra Pairs (2022)

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NS pairs

Hand records

Datum value is the average score. Where a bracketed value is included this is calculated without the outliers.

Detailed data for

Alexandra Pairs (2022) 25 May

NS pair 1

Section b

Alan Chisholm
Judy Henderson

Bd	Rd	Con	Dc	Ld	Res	EW	Score	MP
1	1	1	E	2	+3	1	-130	5
2	1	5	N	4	=	1	650	7
3	1	1 NT	S	7	-1	1	-50	4
4	1	3 NT	E	3	+2	1	-660	0
5	1	2	W	7	+1	1	-140	2
6	2	4	S	A	=	5	420	8
7	2	3	N	6	=	5	140	5
8	2	3	W	A	=	5	-110	1
9	2	3	E	K	+1	5	-170	7
10	2	3 NT	W	8	=	5	-600	0
11	3	4	S	7	+1	4	450	4
12	3	4	E	K	-1	4	050	8
13	3	2	E	6	=	4	-110	5
14	3	4	S	8	-1	4	-50	4
15	3	4	E	6	+3	4	-510	4
16	4	2	S	2	-5	3	-250	2
17	4	2	E	J	-1	3	050	4
18	4	1	E	A	+2	3	-140	5
19	4	4	N	A	+1	3	450	6
20	4	4 NT	W	K	+2	3	-690	4
21	5	1 NT	N	3	+1	2	120	7
22	5	3 NT	W	2	-3	2	300	8
23	5	4	S	K	-1	2	-100	3
24	5	4	E	A	+1	2	-450	3
25	5	2	W	5	-1	2	100	3

NS pair 2

Section b

Robyn Peel
Plony Belt

Bd	Rd	Con	Dc	Ld	Res	EW	Score	MP
1	5	1	E	K	+2	3	-110	8
2	5	5	E	J	-3	3	150	0
3	5	1 NT	S	6	-2	3	-100	1
4	5	1	E	K	+1	3	-110	8
5	5	4	S	5	-1	3	-100	4
6	1	1 NT	E	8	-4	2	400	6
7	1	4	S	7	+1	2	650	8
8	1	3	N	A	-2	2	-100	4
9	1	3	E	6	+1	2	-170	7
10	1	2	W	4	+1	2	-140	3
11	2	4	S	T	+1	1	450	4
12	2	4	E	4	+2	1	-480	0
13	2	3	E	T	=	1	-140	0
14	2	4	S	6	-1	1	-50	4
15	2	6	E	A	=	1	-980	1
16	3	2	E	A	+2	5	-130	6
17	3	4	W	3	-2	5	100	6
18	3	3 NT	W	3	+1	5	-430	0
19	3	4	N	A	=	5	420	2
20	3	6 NT	E	6	=	5	-1440	0
21	4	1 NT	N	3	=	4	090	4
22	4	3 NT	W	8	-1	4	100	4
23	4	4	S	K	-1	4	-100	3
24	4	4	E	A	+1	4	-450	3
25	4	3	E	A	-2	4	200	6

NS pair 3

Section b

Susan Douglas
Kathy McLean

Bd	Rd	Con	Dc	Ld	Res	EW	Score	MP
1	4	3	E	3	+1	5	-130	5
2	4	4 x	E	3	-3	5	500	4
3	4	1 NT x	S	6	-1	5	-100	1
4	4	4	E	2	+1	5	-650	2
5	4	1 NT	N		+3	5	180	6
6	5	1 NT	E	J	+1	4	-120	0
7	5	4	S		-1	4	-100	1
8	5	2 NT	W	5	-4	4	200	8
9	5	4	E	8	+1	4	-650	0
10	5	2	W	4	+2	4	-130	6
11	1	4	S	9	+1	3	450	4
12	1	3 NT	W	K	+1	3	-430	2
13	1	2	E	2	=	3	-110	5
14	1	4	S	8	-3	3	-150	0
15	1	4	E	9	+2	3	-480	6
16	2	3	N	A	-1	2	-50	8
17	2	3	W	6	=	2	-140	0
18	2	1	E	A	+2	2	-140	5
19	2	4	N	A	+1	2	450	6
20	2	2	E	6	+4	2	-170	8
21	3	1 NT	N	2	+1	1	120	7
22	3	3 NT	W	Q	-2	1	200	6
23	3	4	S		-1	1	-100	3
24	3	4	E	A	+1	1	-450	3
25	3	2	N	Q	-1	1	-50	0

NS pair 4

Section b

Pat Hart
Jocelyn Evans

Bd	Rd	Con	Dc	Ld	Res	EW	Score	MP
1	3	1 NT	E	4	+3	2	-180	2
2	3	4 x	E	6	-2	2	300	2
3	3	1 NT	S	6	=	2	090	7
4	3	3	E	2	+1	2	-170	6
5	3	3	S	A	-2	2	-200	0
6	4	3	S	J	+1	1	170	3
7	4	4	N	6	-1	1	-100	1
8	4	3	W	A	=	1	-110	1
9	4	3	E	K	+2	1	-200	4
10	4	4	W	A	-1	1	100	8
11	5	4	S	K	+1	5	450	4
12	5	4	E	4	=	5	-420	5
13	5	3	E	A	-1	5	100	8
14	5	2	S	6	+1	5	140	8
15	5	3	E	2	+4	5	-260	8
16	1	3	W	T	+2	4	-150	4
17	1	2	E	A	=	4	-110	2
18	1	1	E	A	+2	4	-140	5
19	1	3	N	A	=	4	140	0
20	1	3 NT	E	J	+3	4	-690	4
21	2	2	N	5	-3	3	-300	0
22	2	4	E	A	=	3	-620	0
23	2	4	S	Q	-1	3	-100	3
24	2	5	E	A	=	3	-450	3
25	2	3 NT	E	2	-3	3	300	8

NS pair 5

Section b

Joy Sinclair
Ron Hallberg

Bd	Rd	Con	Dc	Ld	Res	EW	Score	MP
1	2	3 NT	E	4	+1	4	-430	0
2	2	5	N	3	=	4	650	7
3	2	1 NT	S	6	=	4	090	7
4	2	4	E	2	=	4	-620	4
5	2	3 NT	N	5	+1	4	630	8
6	3	2	S	2	+2	3	170	3
7	3	2	S	5	+1	3	140	5
8	3	2 NT	W	5	-3	3	150	6
9	3	4	E	K	=	3	-620	2
10	3	2	W	4	+1	3	-140	3
11	4	4	S	7	+1	2	450	4
12	4	4	E	4	=	2	-420	5
13	4	2 NT	E	3	=	2	-120	2
14	4	3	S	8	-1	2	-50	4
15	4	6	E	A	=	2	-980	1
16	5	4 x	N	J	-3	1	-500	0
17	5	4	E	2	-3	1	150	8
18	5	1	E	A	+2	1	-140	5
19	5	4	N	A	+1	1	450	6
20	5	3 NT	E	Q	+3	1	-690	4
21	1	2 NT	N	4	-1	5	-100	2
22	1	3	W	2	=	5	-140	2
23	1	5	E	A	-1	5	100	8
24	1	2	E	A	+3	5	-200	8
25	1	2	E	A	-1	5	100	3