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NS pairs

EW pairs

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Hand records



Datum value is the average score. Where a bracketed value is included this is calculated without the outliers.

Pannett Memorial Pairs (2024) 26 June

EW pair 1 Section b Joy Sinclair Ethel Bristow	Bd Rd Con Dc Ld Res NS   Score   MP 1 1 2 N 2 -3 1 -150 5 2 1 2 W A = 1 -110 6 3 1 2 NT S 3 +3 1 210 4 4 1 3 NT S 4 +2 1 660 0 5 1 3 NT E 2 = 1 -400 6 6 1 3 NT N 6 +3 1 490 3 7 3 5 E 2 = 3 -600 5 8 3 5 x S J -3 3 -500 6 9 3 2 NT E 4 +2 3 -180 0 10 3 2 S A = 3 110 2 11 3 2 E 2 -1 3 050 0 12 3 2 E 7 +1 3 -140 5 13 2 3 N A -3 2 -300 6 14 2 5 W 6 -3 2 150 2 15 2 5 S 7 -1 2 -100 6 16 2 4 S 3 = 2 420 0 17 2 2 N 3 -1 2 -50 5 18 2 1 NT E 2 -1 2 050 1 19 4 1 NT S 4 +1 4 120 0 20 4 2 S A -2 4 -200 6 21 4 5 S T -2 4 -200 6 22 4 3 NT N 3 +4 4 520 1 23 4 6 NT W 2 = 4 -1440 1 24 4 1 NT S 5 -3 4 -150 6
EW pair 2 Section b Kathleen Hurr Jean Bonsor	Bd Rd Con Dc Ld Res NS   Score   MP 1 2 2 N 2 -3 3 -150 5 2 2 3 W -3 3 150 2 3 2 3 NT S 3 +1 3 430 2 4 2 3 NT S 4 +1 3 630 3 5 2 2 E 4 +2 3 -130 0 6 2 3 NT N 5 +3 3 490 3 7 1 3 E 3 +1 2 -130 2 8 1 4 S J -2 2 -100 0 9 1 4 W A = 2 -620 6 10 1 3 S A -1 2 -100 6 11 1 PASS N 2 0 2 12 1 3 E A -2 2 100 2 13 3 1 NT W 5 +1 4 -120 1 14 3 4 S A -1 4 -50 6 15 3 4 NT S K +1 4 660 0 16 3 4 S 8 -2 4 -100 3 17 3 1 NT N T -1 4 -50 5 18 3 1 NT E 2 -1 4 050 1 19 4 1 NT S 4 = 1 090 5 20 4 2 NT S 2 -1 1 -100 4 21 4 2 NT W K -2 1 100 0 22 4 3 NT N 4 +3 1 490 4 23 4 6 NT W 3 +1 1 -1470 5 24 4 2 W J +1 1 -110 4
EW pair 3 Section b John Bates Susan Douglas	Bd Rd Con Dc Ld Res NS   Score   MP 1 4 2 N 2 -2 2 -100 1 2 4 3 N 3 -1 2 -100 4 3 4 1 NT N 2 -1 2 -50 6 4 4 3 S 7 +1 2 130 6 5 4 1 NT E 2 +2 2 -150 2 6 4 3 NT N 3 +3 2 490 3 7 2 5 E K = 4 -600 5 8 2 5 S J -3 4 -150 2 9 2 3 NT E 4 = 4 -600 3 10 2 2 S A = 4 110 2 11 2 2 E 4 +2 4 -130 6 12 2 2 NT N 3 = 4 120 0 13 3 2 NT W 2 = 1 -120 1 14 3 1 S T +2 1 140 4 15 3 3 S A +2 1 150 4 16 3 2 x E 8 = 1 -180 6 17 3 2 S 5 = 1 110 0 18 3 1 NT E 2 = 1 -90 5 19 1 1 NT S 4 = 3 090 5 20 1 1 NT W 5 = 3 -90 2 21 1 2 E 2 +2 3 -170 4 22 1 5 S K +1 3 420 6 23 1 6 NT W 7 = 3 -1440 1 24 1 1 NT S A +3 3 180 0
EW pair 4 Section b Elisabeth Hinton Nigel Hinton	Bd Rd Con Dc Ld Res NS   Score   MP 1 1 2 N 2 -2 4 -100 1 2 1 3 NT N 3 = 4 600 0 3 1 3 NT S 3 +2 4 460 0 4 1 3 NT S 4 +1 4 630 3 5 1 2 NT E 4 +2 4 -180 4 6 1 3 NT N 5 +3 4 490 3 7 2 4 W 3 -2 1 200 0 8 2 5 E A +1 1 -480 4 9 2 3 NT E 8 = 1 -600 3 10 2 2 S A = 1 110 2 11 2 3 E J = 1 -110 4 12 2 3 E K = 1 -140 5 13 4 1 NT E 4 +3 3 -180 4 14 4 4 x S T = 3 510 0 15 4 5 S 7 = 3 600 2 16 4 4 S 8 -2 3 -100 3 17 4 1 NT N 8 = 3 090 2 18 4 1 NT E 2 = 3 -90 5 19 3 2 E 4 -1 2 100 2 20 3 2 N J +1 2 110 0 21 3 2 E A +1 2 -140 2 22 3 5 NT S K +2 2 520 1 23 3 6 NT E 3 +1 2 -1470 5 24 3 2 N J = 2 090 2